Mathematics

Mathematics

Problem

Let f:R→Rf:\mathbb R\to\mathbb R be defined by f(x)=ax+bf(x)=ax+b and g:R→Rg:\mathbb R\to\mathbb R by g(x)=cx+dg(x)=cx+d, where a,c≠0a,c\neq 0. For ff and gg to be mutual inverses, which one of the following sets of conditions on the constants must hold? a) ac=1,  ad−b=0,  cb+d=0ac=1,\; ad-b=0,\; cb+d=0 b) ac=1,  ad+b=0,  cb−d=0ac=1,\; ad+b=0,\; cb-d=0 c) ac=1,  ad+b=0,  cb+d=0ac=1,\; ad+b=0,\; cb+d=0 d) ac=−1,  ad+b=0,  cb+d=0ac=-1,\; ad+b=0,\; cb+d=0

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