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Mathematics
Mathematics
Problem
The piecewise function
p
p
p
is defined as
p
(
x
)
=
{
p
x
+
3
,
x
<
2
x
2
−
p
2
,
x
≥
2
p(x)=\begin{cases} px+3,& x<2\\ x^{2}-p^{2},& x\ge 2 \end{cases}
p
(
x
)
=
{
p
x
+
3
,
x
2
−
p
2
,
x
<
2
x
≥
2
For which real value(s) of
p
p
p
does
lim
x
→
2
p
(
x
)
\displaystyle\lim_{x\to 2}p(x)
x
→
2
lim
p
(
x
)
exist? a)
p
=
1
p=1
p
=
1
b) both
−
1
+
2
-1+\sqrt{2}
−
1
+
2
and
−
1
−
2
-1-\sqrt{2}
−
1
−
2
c)
p
=
−
1
+
2
p=-1+\sqrt{2}
p
=
−
1
+
2
only d)
1
3
\dfrac{1}{3}
3
1
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