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Mathematics
Mathematics
Problem
Let
p
(
x
)
=
⌊
∣
x
−
1
∣
⌋
+
sgn
(
x
+
2
)
p(x)=\lfloor |x-1| \rfloor + \operatorname{sgn}(x+2)
p
(
x
)
=
⌊
∣
x
−
1∣
⌋
+
sgn
(
x
+
2
)
. a. (i) Find
p
(
−
2
)
p(-2)
p
(
−
2
)
. b. (ii) Find
p
(
0.3
)
p(0.3)
p
(
0.3
)
. c. (iii) Find
p
(
2.8
)
p(2.8)
p
(
2.8
)
. d. (iv) Hence calculate
p
(
−
2
)
+
p
(
0.3
)
+
p
(
2.8
)
p(-2)+p(0.3)+p(2.8)
p
(
−
2
)
+
p
(
0.3
)
+
p
(
2.8
)
.}],
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