Energy Flow Through Empty Space: Poynting's Hidden Highway · AI Deep Generator #DEEP-FC3FC806

Physics · electromagnetism · modern-physics

Problem

A coaxial cable carries steady current I0I_0 from a battery of voltage V0V_0. The inner conductor has radius aa, the outer conductor has inner radius bb, and the space between them is vacuum. The cable has length L≫bL \gg b and the conductors have negligible resistance. (a) [8 pt] Find the electric field E⃗(r)\vec{E}(r) and magnetic field B⃗(r)\vec{B}(r) in the region a<r<ba < r < b between the conductors. Express your answer in cylindrical coordinates (r,ϕ,z)(r, \phi, z) with zz along the cable axis. (b) [10 pt] Calculate the Poynting vector S⃗=1μ0E⃗×B⃗\vec{S} = \frac{1}{\mu_0}\vec{E} \times \vec{B} in this region. Show that the total electromagnetic power flow through any cross-section equals V0I0V_0 I_0. (c) [12 pt] The electromagnetic field carries momentum density g⃗=ϵ0E⃗×B⃗\vec{g} = \epsilon_0 \vec{E} \times \vec{B}. Find the total electromagnetic momentum stored in the cable. Express your result in terms of the cable's inductance Lcable=μ0L2πln⁡(ba)L_{\text{cable}} = \frac{\mu_0 L}{2\pi} \ln\left(\frac{b}{a}\right). (d) [10 pt] At t=0t = 0, the circuit is suddenly broken at one end. During the transient, the current decreases as I(t)=I0e−t/τI(t) = I_0 e^{-t/\tau} where τ=Lcable/Rload\tau = L_{\text{cable}}/R_{\text{load}} and RloadR_{\text{load}} is the load resistance. Find the rate of change of electromagnetic momentum in the cable. (e) [12 pt] During the current decay, electromagnetic waves are radiated from the cable ends. Using momentum conservation, find the net radiation pressure force on the cable system. Explain the physical origin of this force. (f) [12 pt] The radiated power can be estimated as Prad=μ0c6π(dIdt)2AeffP_{\text{rad}} = \frac{\mu_0 c}{6\pi}\left(\frac{dI}{dt}\right)^2 A_{\text{eff}} where Aeff=π(b2−a2)A_{\text{eff}} = \pi(b^2 - a^2) is the effective radiating area. Find the total energy radiated during the current decay. (g) [12 pt] Compare the radiated energy to the initial stored magnetic energy UB=12LcableI02U_B = \frac{1}{2}L_{\text{cable}}I_0^2. Show that for Rload≫μ0cAeff3πLcableR_{\text{load}} \gg \sqrt{\frac{\mu_0 c A_{\text{eff}}}{3\pi L_{\text{cable}}}}, radiation is negligible. (h) [14 pt] For a numerical example, consider a=1a = 1 mm, b=3b = 3 mm, L=10L = 10 m, I0=1I_0 = 1 A, and Rload=50R_{\text{load}} = 50 Ω. Calculate: (i) the initial electromagnetic momentum, (ii) the radiation recoil force, and (iii) the fraction of energy radiated. Comment on why coaxial cables are excellent for containing electromagnetic energy.

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