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Mathematics
Problem
Consider
p
(
x
)
=
∣
x
−
3
∣
+
9
x
p(x)=|x-3|+\dfrac{9}{x}
p
(
x
)
=
∣
x
−
3∣
+
x
9
on the interval
[
1
,
6
]
[1,6]
[
1
,
6
]
. At what value of
x
x
x
does
p
p
p
attain its absolute minimum on this interval? a)
x
=
6
x=6
x
=
6
b) No absolute minimum on
[
1
,
6
]
[1,6]
[
1
,
6
]
c)
x
=
3
x=3
x
=
3
d)
x
=
1
x=1
x
=
1
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