A 12V ideal battery is connected to the network shown: starting from the positive terminal, current I1 flows through a 2Ω resistor to a junction C, then splits into currents I2 through a 4Ω resistor and I3 through a 6Ω resistor, both reaching the negative terminal of the battery. Given that I1=I2+I3, determine the power dissipated in the 6Ω resistor.
a) 8.6W
b) 6.5W
c) 7.1W
d) 11.1W