Electricity and Magnetism · Problem 7.10

ALTERNATING-CURRENT CIRCUITS — Edward Purcell & David Morin

Physics — E&M · mutual-inductance-symmetry

Problem

Mutual-inductance symmetry ** In Section 7.7 we made use of the vector potential to prove that M12=M21M_{12} = M_{21}. We can give a second proof, this time in the spirit of Exercise 3.64. Imagine increasing the currents in two circuits gradually from zero to the final values of I1fI_{1f} and I2fI_{2f} (``f'' for ``final''). Due to the induced emfs, some external agency has to supply power to increase (or maintain) the currents. The final currents can be brought about in many different ways. Two possible ways are of particular interest. ((a)) Keep I2I_2 at zero while raising I1I_1 gradually from zero to I1fI_{1f}. Then raise I2I_2 from zero to I2fI_{2f} while holding I1I_1 constant at I1fI_{1f}. ((b)) Carry out a similar program with the roles of 1 and 2 exchanged, that is, raise I2I_2 from zero to I2fI_{2f} first, and so on. Compute the total work done by external agencies, for each of the two programs. Then complete the argument. See Crawford (1992) for further discussion.

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