Physics

Problem

A stone is thrown horizontally from a tower of unknown height

H

. It strikes the ground with a velocity vector having a magnitude of

50\,\text{m/s}

directed at an angle of

53^{\circ}

below the horizontal. Find the height

H

of the tower. Also if the

40\%

kinetic energy is lost in the impact then calculate the

x

coordinate of second impact point (Take

g = 10\,\text{m/s}^{2}

\sin 53^{\circ} = 0.8

\cos 53^{\circ} = 0.6

, assume the ground surface is frictionless)