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Physics
Physics
Problem
A projectile is given an initial velocity of
(
i
^
+
2
j
^
)
(\hat{i} + 2\hat{j})
(
i
^
+
2
j
^
)
m/s, where
i
^
\hat{i}
i
^
is along the ground and
j
^
\hat{j}
j
^
is along the vertical. If
g
=
10
g = 10
g
=
10
m/s
2
^2
2
, the equation of its trajectory is : [2013] (a)
y
=
x
−
5
x
2
y = x - 5x^2
y
=
x
−
5
x
2
(b)
y
=
2
x
−
5
x
2
y = 2x - 5x^2
y
=
2
x
−
5
x
2
(c)
4
y
=
2
x
−
5
x
2
4y = 2x - 5x^2
4
y
=
2
x
−
5
x
2
(d)
4
y
=
2
x
−
25
x
2
4y = 2x - 25x^2
4
y
=
2
x
−
25
x
2
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