Mathematics

Mathematics

Problem

If dydx=xyx2+y2\frac{dy}{dx} = \frac{xy}{x^2 + y^2} ; y(1)=1y(1) = 1 ; then a value of xx satisfying y(x)=ey(x) = e is : [JEE-MAIN ONLINE-2020] (1) 2e\sqrt{2}e (2) e2\frac{e}{\sqrt{2}} (3) 123e\frac{1}{2}\sqrt{3}e (4) 3e\sqrt{3}e

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