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Mathematics
Mathematics
Problem
Prove that
sin
(
B
−
C
)
cos
B
cos
C
+
sin
(
C
−
A
)
cos
C
cos
A
+
sin
(
A
−
B
)
cos
A
cos
B
=
0
\frac{\sin(B-C)}{\cos B \cos C} + \frac{\sin(C-A)}{\cos C \cos A} + \frac{\sin(A-B)}{\cos A \cos B} = 0
cos
B
cos
C
sin
(
B
−
C
)
+
cos
C
cos
A
sin
(
C
−
A
)
+
cos
A
cos
B
sin
(
A
−
B
)
=
0
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