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Mathematics
Mathematics
Problem
Which of the following is the correct identity for
tan
2
θ
\tan 2\theta
tan
2
θ
? a)
2
tan
θ
1
+
tan
2
θ
\dfrac{2\tan\theta}{1+\tan^{2}\theta}
1
+
tan
2
θ
2
tan
θ
b)
1
−
tan
2
θ
2
tan
θ
\dfrac{1-\tan^{2}\theta}{2\tan\theta}
2
tan
θ
1
−
tan
2
θ
c)
2
tan
θ
1
−
tan
2
θ
\dfrac{2\tan\theta}{1-\tan^{2}\theta}
1
−
tan
2
θ
2
tan
θ
d)
2
tan
θ
(
1
−
tan
2
θ
)
2\tan\theta\,(1-\tan^{2}\theta)
2
tan
θ
(
1
−
tan
2
θ
)
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