Mathematics

Mathematics

Problem

## EXERCISE 1.4 1. Classify the following numbers as rational or irrational: (i) 2−52-\sqrt{5} (ii) (3+23)−23(3+\sqrt{23})-\sqrt{23} (iii) 2777\frac{2 \sqrt{7}}{7 \sqrt{7}} (iv) 12\frac{1}{\sqrt{2}} (v) 2π2 \pi 2. Simplify each of the following expressions: (i) (3+3)(2+2)(3+\sqrt{3})(2+\sqrt{2}) (ii) (3+3)(3−3)(3+\sqrt{3})(3-\sqrt{3}) (iii) (5+2)2(\sqrt{5}+\sqrt{2})^{2} (iv) (5−2)(5+2)(\sqrt{5}-\sqrt{2})(\sqrt{5}+\sqrt{2}) 3. Recall, π\pi is defined as the ratio of the circumference (say cc ) of a circle to its diameter (say dd ). That is, π=cd\pi=\frac{c}{d}. This seems to contradict the fact that π\pi is irrational. How will you resolve this contradiction? 4. Represent 9.3\sqrt{9.3} on the number line. 5. Rationalise the denominators of the following: (i) 17\frac{1}{\sqrt{7}} (ii) 17−6\frac{1}{\sqrt{7}-\sqrt{6}} (iii) 15+2\frac{1}{\sqrt{5}+\sqrt{2}} (iv) 17−2\frac{1}{\sqrt{7}-2} (i) 2−52-\sqrt{5} (ii) (3+23)−23(3+\sqrt{23})-\sqrt{23} (iii) 2777\frac{2 \sqrt{7}}{7 \sqrt{7}} (iv) 12\frac{1}{\sqrt{2}} (v) 2π2 \pi

Browse the problem library