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Physics
Physics
Problem
Which of the following expressions gives the acceleration due to gravity
g
g
g
in terms of the length
L
L
L
of a simple pendulum and its time period
T
T
T
? a)
g
=
2
π
L
T
2
g = \dfrac{2\pi L}{T^{2}}
g
=
T
2
2
π
L
b)
g
=
π
2
L
T
2
g = \dfrac{\pi^{2}L}{T^{2}}
g
=
T
2
π
2
L
c)
g
=
4
π
2
L
T
2
g = \dfrac{4\pi^{2}L}{T^{2}}
g
=
T
2
4
π
2
L
d)
g
=
16
π
2
L
T
2
g = \dfrac{16\pi^{2}L}{T^{2}}
g
=
T
2
16
π
2
L
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