Physics

Physics

Problem

Which of the following expressions gives the acceleration due to gravity gg in terms of the length LL of a simple pendulum and its time period TT? a) g=2πLT2g = \dfrac{2\pi L}{T^{2}} b) g=π2LT2g = \dfrac{\pi^{2}L}{T^{2}} c) g=4π2LT2g = \dfrac{4\pi^{2}L}{T^{2}} d) g=16π2LT2g = \dfrac{16\pi^{2}L}{T^{2}}

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