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Physics
Physics
Problem
Consider the decay
92
238
U
→
90
234
Th
+
2
4
α
{}_{92}^{238}\text{U} \rightarrow {}_{90}^{234}\text{Th} + {}_{2}^{4}\alpha
92
238
U
→
90
234
Th
+
2
4
α
. Calculate the energy released. (Binding energy per nucleon:
U
=
7.57
MeV
\text{U} = 7.57 \text{ MeV}
U
=
7.57
MeV
;
Th
=
7.60
MeV
\text{Th} = 7.60 \text{ MeV}
Th
=
7.60
MeV
;
He
=
7.07
MeV
\text{He} = 7.07 \text{ MeV}
He
=
7.07
MeV
.)
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