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Mathematics
Problem
If
cos
θ
=
−
7
25
\cos\theta = -\dfrac{7}{25}
cos
θ
=
−
25
7
and
θ
\theta
θ
lies in Quadrant III, calculate
1
−
2
sin
2
θ
1-2\sin^{2}\theta
1
−
2
sin
2
θ
. a)
49
625
\dfrac{49}{625}
625
49
b)
−
527
625
-\dfrac{527}{625}
−
625
527
c)
527
625
\dfrac{527}{625}
625
527
d)
337
625
\dfrac{337}{625}
625
337
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