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Mathematics
Mathematics
Problem
The solution of the differential equation,
e
x
(
x
+
1
)
d
x
+
(
y
e
y
−
x
e
x
)
d
y
=
0
e^x(x+1)dx + (ye^y - xe^x)dy = 0
e
x
(
x
+
1
)
d
x
+
(
y
e
y
−
x
e
x
)
d
y
=
0
with initial condition
f
(
0
)
=
0
f(0) = 0
f
(
0
)
=
0
, is - (A)
x
e
x
+
2
y
2
e
y
=
0
xe^x + 2y^2e^y = 0
x
e
x
+
2
y
2
e
y
=
0
(B)
2
x
e
x
+
y
2
e
y
=
0
2xe^x + y^2e^y = 0
2
x
e
x
+
y
2
e
y
=
0
(C)
x
e
x
−
2
y
2
e
y
=
0
xe^x - 2y^2e^y = 0
x
e
x
−
2
y
2
e
y
=
0
(D)
2
x
e
x
−
y
2
e
y
=
0
2xe^x - y^2e^y = 0
2
x
e
x
−
y
2
e
y
=
0
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