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Mathematics
Problem
The sides AB, BC, CD and DA of a quadrilateral have the equations
x
+
2
y
=
3
x + 2y = 3
x
+
2
y
=
3
,
x
=
1
x = 1
x
=
1
,
x
−
3
y
=
4
x - 3y = 4
x
−
3
y
=
4
,
5
x
+
y
+
12
=
0
5x + y + 12 = 0
5
x
+
y
+
12
=
0
respectively, then the angle between the diagonals AC and BD is :- (1)
60
∘
60^\circ
6
0
∘
(2)
45
∘
45^\circ
4
5
∘
(3)
90
∘
90^\circ
9
0
∘
(4) None of these
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