Mathematics

Mathematics

Problem

In △ABC\triangle ABC, points DD on ABAB and EE on ACAC are such that DE∥BCDE \parallel BC. Given AD=8 cmAD = 8\,\text{cm}, DB=12 cmDB = 12\,\text{cm} and AC=9 cmAC = 9\,\text{cm}. A line through DD parallel to ACAC meets BCBC at FF. If BC=15 cmBC = 15\,\text{cm}, then the length BFBF (in cm) is a) 66 b) 1212 c) 99 d) 1010

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