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Chemistry
Chemistry
Problem
Cu
+
+
e
−
→
Cu
\text{Cu}^+ + \text{e}^- \rightarrow \text{Cu}
Cu
+
+
e
−
→
Cu
,
E
∘
=
x
1
volt
E^{\circ} = x_1\ \text{volt}
E
∘
=
x
1
volt
;
Cu
2
+
+
2
e
−
→
Cu
\text{Cu}^{2+} + 2\text{e}^- \rightarrow \text{Cu}
Cu
2
+
+
2
e
−
→
Cu
,
E
∘
=
x
2
volt
E^{\circ} = x_2\ \text{volt}
E
∘
=
x
2
volt
, then for
Cu
2
+
+
e
−
→
Cu
+
\text{Cu}^{2+} + \text{e}^- \rightarrow \text{Cu}^+
Cu
2
+
+
e
−
→
Cu
+
,
E
∘
E^{\circ}
E
∘
(volt) will be: (a)
x
1
−
2
x
2
x_1 - 2x_2
x
1
−
2
x
2
(b)
x
1
+
2
x
2
x_1 + 2x_2
x
1
+
2
x
2
(c)
x
1
−
x
2
x_1 - x_2
x
1
−
x
2
(d)
2
x
2
−
x
1
2x_2 - x_1
2
x
2
−
x
1
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