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Mathematics
Mathematics
Problem
If
tan
−
1
x
+
2
cot
−
1
x
=
2
π
3
\tan^{-1} x + 2 \cot^{-1} x = \frac{2\pi}{3}
tan
−
1
x
+
2
cot
−
1
x
=
3
2
π
, then
x
=
x =
x
=
(a)
2
\sqrt{2}
2
(b) 3 (c)
3
\sqrt{3}
3
(d)
3
−
1
3
+
1
\frac{\sqrt{3}-1}{\sqrt{3}+1}
3
+
1
3
−
1
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