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Mathematics
Mathematics
Problem
Prove that the locus of the centre of the circle
1
2
(
x
2
+
y
2
)
+
x
cos
θ
+
y
sin
θ
−
4
=
0
\frac{1}{2}(x^2 + y^2) + x \cos \theta + y \sin \theta - 4 = 0
2
1
(
x
2
+
y
2
)
+
x
cos
θ
+
y
sin
θ
−
4
=
0
is
x
2
+
y
2
=
1
x^2 + y^2 = 1
x
2
+
y
2
=
1
.
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