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Mathematics
Mathematics
Problem
Solve
sin
2
x
=
3
2
\sin 2x = \dfrac{\sqrt{3}}{2}
sin
2
x
=
2
3
for all values of
x
x
x
in the interval
0
∘
≤
x
≤
360
∘
0^{\circ}\le x \le 360^{\circ}
0
∘
≤
x
≤
36
0
∘
.
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