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Mathematics
Mathematics
Problem
If the lines
x
−
1
−
3
=
y
−
2
2
λ
=
z
−
3
2
\frac{x-1}{-3} = \frac{y-2}{2\lambda} = \frac{z-3}{2}
−
3
x
−
1
=
2
λ
y
−
2
=
2
z
−
3
and
x
−
1
3
λ
=
y
−
1
1
=
6
−
z
5
\frac{x-1}{3\lambda} = \frac{y-1}{1} = \frac{6-z}{5}
3
λ
x
−
1
=
1
y
−
1
=
5
6
−
z
are perpendicular to each other then find the value of
λ
\lambda
λ
.
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