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Mathematics
Problem
The Taylor series for
h
(
x
)
=
ln
x
h(x)=\ln x
h
(
x
)
=
ln
x
centered at
x
=
2
x=2
x
=
2
can be written as
h
(
x
)
=
∑
n
=
0
∞
b
n
(
x
−
2
)
n
h(x)=\sum_{n=0}^{\infty} b_n (x-2)^n
h
(
x
)
=
∑
n
=
0
∞
b
n
(
x
−
2
)
n
for
∣
x
−
2
∣
<
2
|x-2|<2
∣
x
−
2∣
<
2
. What is the value of
b
3
b_3
b
3
? a)
−
1
24
-\dfrac{1}{24}
−
24
1
b)
1
12
\dfrac{1}{12}
12
1
c)
1
24
\dfrac{1}{24}
24
1
d)
1
4
\dfrac{1}{4}
4
1
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