Physics

Physics

Problem

You are given that mass of 37Li=7.0160 u{}^7_3\text{Li} = 7.0160 \text{ u} , Mass of 24He=4.0026 u{}^4_2\text{He} = 4.0026 \text{ u} and Mass of 11H=1.0079 u{}^1_1\text{H} = 1.0079 \text{ u} . When 20 g of 37Li{}^7_3\text{Li} is converted into 24He{}^4_2\text{He} by proton capture, the energy liberated, (in kWh), is : a. 4.5×1054.5 \times 10^5 b. 8×1068 \times 10^6 c. 6.82×1056.82 \times 10^5 d. 1.33×1061.33 \times 10^6

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