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Mathematics
Problem
If the velocity of a particle is
v
=
A
t
+
B
t
2
v = At + Bt^2
v
=
A
t
+
B
t
2
, where
A
A
A
and
B
B
B
are constants, then the distance travelled by it between 1 s and 2 s is: a.
3
2
A
+
4
B
\frac{3}{2}A + 4B
2
3
A
+
4
B
b.
3
A
+
7
B
3A + 7B
3
A
+
7
B
c.
3
2
A
+
7
3
B
\frac{3}{2}A + \frac{7}{3}B
2
3
A
+
3
7
B
d.
A
2
+
B
3
\frac{A}{2} + \frac{B}{3}
2
A
+
3
B
a.
3
2
A
+
4
B
\frac{3}{2}A + 4B
2
3
A
+
4
B
b.
3
A
+
7
B
3A + 7B
3
A
+
7
B
c.
3
2
A
+
7
3
B
\frac{3}{2}A + \frac{7}{3}B
2
3
A
+
3
7
B
d.
A
2
+
B
3
\frac{A}{2} + \frac{B}{3}
2
A
+
3
B
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