Mathematics

Mathematics

Problem

On the interval I=[−2,2]I = [-2, 2], if the function f(x)={(x+1)e−(1∣x∣+1x),x≠0,0,x=0f(x) = \begin{cases} (x+1)e^{-\left(\frac{1}{|x|} + \frac{1}{x}\right)}, & x \neq 0, \\ 0, & x = 0 \end{cases} then which of the following hold good? a. f(x)f(x) is continuous for all values of x∈Ix \in I b. f(x)f(x) is continuous for x∈I−{0}x \in I - \{0\} c. f(x)f(x) assumes all intermediate values from f(−2)f(-2) to f(2)f(2) d. f(x)f(x) has a maximum value equal to 3/e3/e

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