Problem

Problem

Assertion : Minimum deviation by an equilateral prism of refractive index 2\sqrt{2} is 30∘30^\circ . Reason : It is from the relation, μ=sin⁡(A+δm2)sin⁡(A2)\mu = \frac{\sin\left(\frac{A + \delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}

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