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Problem
Problem
Consider the equations
5
sin
2
x
+
3
sin
x
cos
x
−
3
cos
2
x
=
2
…
(
i
)
5\sin^2 x + 3\sin x \cos x - 3\cos^2 x = 2 \quad \dots(i)
5
sin
2
x
+
3
sin
x
cos
x
−
3
cos
2
x
=
2
…
(
i
)
sin
2
x
−
cos
2
x
=
2
−
sin
2
x
…
(
i
i
)
\sin^2 x - \cos 2x = 2 - \sin 2x \quad \dots(ii)
sin
2
x
−
cos
2
x
=
2
−
sin
2
x
…
(
ii
)
If
α
\alpha
α
is a root of (i) and
β
\beta
β
is a root of (ii), then
tan
α
+
tan
β
\tan \alpha + \tan \beta
tan
α
+
tan
β
can be equal to a.
1
+
69
/
6
1 + \sqrt{69}/6
1
+
69
/6
b.
−
1
−
69
/
6
-1 - \sqrt{69}/6
−
1
−
69
/6
c.
−
3
+
69
6
\frac{-3 + \sqrt{69}}{6}
6
−
3
+
69
d.
3
−
69
3
\frac{3 - \sqrt{69}}{3}
3
3
−
69
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