Problem

Problem

Match the column.
Column IColumn II
(A) lim⁡x→01−cos⁡2xex2−ex+x\lim_{x \to 0} \frac{1 - \cos 2x}{e^{x^2} - e^x + x} equals(p) 1
(B) If the value of lim⁡x→0+((3/x)+1(3/x)−1)1/x\lim_{x \to 0^+} \left( \frac{(3/x) + 1}{(3/x) - 1} \right)^{1/x} can be expressed in the form of ep/qe^{p/q} , where pp and qq are relative prime, then (p+q)(p + q) is equal to(q) 2
(C) lim⁡x→0tan⁡3x−tan⁡x3x5\lim_{x \to 0} \frac{\tan^3 x - \tan x^3}{x^5} equals(r) 4
(D) lim⁡x→0x+2sin⁡xx2+2sin⁡x+1−sin⁡2x−x+1\lim_{x \to 0} \frac{x + 2 \sin x}{\sqrt{x^2 + 2 \sin x + 1} - \sqrt{\sin^2 x - x + 1}} equals(s) 5

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