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∫
e
2
x
(
sin
4
x
−
2
1
−
cos
4
x
)
d
x
=
\int e^{2x} \left( \frac{\sin 4x - 2}{1 - \cos 4x} \right) dx =
∫
e
2
x
(
1
−
cos
4
x
sin
4
x
−
2
)
d
x
=
Mathematics
Problem
∫
e
2
x
(
sin
4
x
−
2
1
−
cos
4
x
)
d
x
=
\int e^{2x} \left( \frac{\sin 4x - 2}{1 - \cos 4x} \right) dx =
∫
e
2
x
(
1
−
cos
4
x
sin
4
x
−
2
)
d
x
=
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