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Mathematics
Mathematics
Problem
A student solves
d
y
d
x
=
ln
x
\dfrac{dy}{dx}=\ln x
d
x
d
y
=
ln
x
and writes the particular solution satisfying
y
(
1
)
=
2
y(1)=2
y
(
1
)
=
2
in two different ways: (i)
y
=
2
+
∫
1
x
ln
t
d
t
y=2+\displaystyle\int_{1}^{x}\ln t\, dt
y
=
2
+
∫
1
x
ln
t
d
t
(ii)
y
=
∫
0
x
ln
t
d
t
+
C
y=\displaystyle\int_{0}^{x}\ln t\, dt + C
y
=
∫
0
x
ln
t
d
t
+
C
What value of
C
C
C
makes expressions (i) and (ii) equivalent for all
x
>
1
x>1
x
>
1
? a)
1
1
1
b)
3
3
3
c)
2
2
2
d)
0
0
0
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