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Mathematics
Mathematics
Problem
For a particle the displacement–time relation is
x
(
t
)
=
t
3
−
6
t
2
+
9
t
x(t) = t^{3} - 6t^{2} + 9t
x
(
t
)
=
t
3
−
6
t
2
+
9
t
(in metres,
t
t
t
in seconds). a. (i) Find the instants when the particle reverses its direction of motion. b. (ii) Determine the displacement of the particle between
t
=
0
t = 0
t
=
0
and
t
=
6
s
t = 6\,\text{s}
t
=
6
s
.
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