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Mathematics
Problem
If equation
x
2
−
b
x
a
x
−
c
=
k
−
1
k
+
1
\frac{x^2 - bx}{ax - c} = \frac{k-1}{k+1}
a
x
−
c
x
2
−
b
x
=
k
+
1
k
−
1
has roots equal in magnitude & opposite in sign, then the value of k is - (A)
a
+
b
a
−
b
\frac{a+b}{a-b}
a
−
b
a
+
b
(B)
a
−
b
a
+
b
\frac{a-b}{a+b}
a
+
b
a
−
b
(C)
a
b
+
1
\frac{a}{b} + 1
b
a
+
1
(D)
a
b
−
1
\frac{a}{b} - 1
b
a
−
1
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