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Problem
Problem
If the equation
e
∣
x
−
1
∣
−
2
∣
x
∣
+
b
=
−
2
e^{|x-1|} - 2|x| + b = -2
e
∣
x
−
1∣
−
2∣
x
∣
+
b
=
−
2
has four solutions, then
b
b
b
lies in
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