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Mathematics
Problem
If
A
=
[
−
1
0
0
0
1
0
0
0
1
]
A = \begin{bmatrix} -1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}
A
=
−
1
0
0
0
1
0
0
0
1
, then
A
−
1
A^{-1}
A
−
1
is (A)
[
−
1
0
0
0
−
1
0
0
0
−
1
]
\begin{bmatrix} -1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & -1 \end{bmatrix}
−
1
0
0
0
−
1
0
0
0
−
1
(B)
[
1
0
0
0
−
1
0
0
0
−
1
]
\begin{bmatrix} 1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & -1 \end{bmatrix}
1
0
0
0
−
1
0
0
0
−
1
(C)
[
−
1
0
0
0
−
1
0
0
0
1
]
\begin{bmatrix} -1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & 1 \end{bmatrix}
−
1
0
0
0
−
1
0
0
0
1
(D)
[
−
1
0
0
0
1
0
0
0
1
]
\begin{bmatrix} -1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix}
−
1
0
0
0
1
0
0
0
1
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