Problem

Direction of the second maximum in the Fraunhofer diffraction pattern at a single slit is given by (

a

is the width of the slit): (a)

a \sin \theta = \frac{\lambda}{2}

(b)

a \cos \theta = \frac{3\lambda}{2}

(c)

a \sin \theta = \lambda

(d)

a \sin \theta = \frac{3\lambda}{2}