Physics

Physics

Problem

For a particle executing simple harmonic motion with amplitude AA and angular frequency ω\omega, which one of the following expressions gives the magnitude of its velocity vv when its instantaneous displacement from the mean position is xx? a) v=ωA2+x2v = \omega\sqrt{A^{2}+x^{2}} b) v=ω2(A2−x2)v = \omega\sqrt{2\left(A^{2}-x^{2}\right)} c) v=ωA2−x2v = \omega\sqrt{A^{2}-x^{2}} d) v=ωA2−x2Av = \omega\dfrac{A^{2}-x^{2}}{A}

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