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Mathematics
Problem
Solve the equation
sin
2
x
=
2
sin
2
x
\sin 2x=2\sin^{2}x
sin
2
x
=
2
sin
2
x
for all real values of
x
x
x
in the interval
0
≤
x
≤
2
π
0\le x\le2\pi
0
≤
x
≤
2
π
. Show each algebraic step clearly and list every distinct solution in ascending order.
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