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Problem
Problem
Slit 1 of a double slit is wider than slit 2, so that the light from slit 1 has an amplitude three times that of the light from slit 2. Show that equation
I
=
I
max
cos
2
ϕ
2
I = I_{\max} \cos^2 \frac{\phi}{2}
I
=
I
m
a
x
cos
2
2
ϕ
is replaced by the equation,
I
=
(
I
max
4
)
(
1
+
3
cos
2
ϕ
2
)
I = \left( \frac{I_{\max}}{4} \right) \left( 1 + 3 \cos^2 \frac{\phi}{2} \right)
I
=
(
4
I
m
a
x
)
(
1
+
3
cos
2
2
ϕ
)
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