Mathematics

Problem

The image of the line

\frac{x-1}{3} = \frac{y-3}{1} = \frac{z-4}{-5}

in the plane

2x - y + z + 3 = 0

is the line a.

\frac{x+3}{3} = \frac{y-5}{1} = \frac{z-2}{-5}

\frac{x+3}{-3} = \frac{y-5}{-1} = \frac{z+2}{5}

\frac{x-3}{3} = \frac{y+5}{1} = \frac{z-2}{-5}

\frac{x-3}{-3} = \frac{y+5}{-1} = \frac{z-2}{5}