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Mathematics
Mathematics
Problem
Let
g
(
x
)
=
(
x
−
1
)
n
log
cos
m
(
x
−
1
)
g(x) = \frac{(x-1)^n}{\log \cos^m (x-1)}
g
(
x
)
=
l
o
g
c
o
s
m
(
x
−
1
)
(
x
−
1
)
n
,
0
<
x
<
2
0 < x < 2
0
<
x
<
2
, where
m
m
m
and
n
n
n
are integers,
m
≠
0
m \neq 0
m
=
0
,
n
>
0
n > 0
n
>
0
, and let
p
p
p
be the left-hand derivative of
∣
x
−
1
∣
|x-1|
∣
x
−
1∣
at
x
=
1
x=1
x
=
1
. If
lim
x
→
1
+
g
(
x
)
=
p
\lim_{x \to 1^+} g(x) = p
lim
x
→
1
+
g
(
x
)
=
p
, then a.
n
=
1
,
m
=
1
n=1, m=1
n
=
1
,
m
=
1
b.
n
=
1
,
m
=
−
1
n=1, m=-1
n
=
1
,
m
=
−
1
c.
n
=
2
,
m
=
2
n=2, m=2
n
=
2
,
m
=
2
d.
n
>
2
,
m
=
n
n>2, m=n
n
>
2
,
m
=
n
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