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Mathematics
Mathematics
Problem
Consider the system
(
k
+
1
)
x
+
3
y
=
4
,
2
x
+
6
y
=
5.
(k+1)x + 3y = 4,\; 2x + 6y = 5.
(
k
+
1
)
x
+
3
y
=
4
,
2
x
+
6
y
=
5.
For which value of
k
k
k
does the system fail to have a unique solution? a)
1
1
1
b)
−
1
-1
−
1
c)
0
0
0
d)
−
2
-2
−
2
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