Let us return to the problem of the creation of Klein-Gordon particles by a classical source. Recall from Chapter 2 that this process can be described by the Hamiltonian
H=H0+∫d3x(−j(t,x)ϕ(x)),
where H0 is the free Klein-Gordon Hamiltonian, ϕ(x) is the Klein-Gordon field, and j(x) is a c-number scalar function. We found that, if the system is in the vacuum state before the source is turned on, the source will create a mean number of particles
⟨N⟩=∫(2π)3d3p2Ep1∣j~(p)∣2.
In this problem we will verify that statement, and extract more detailed information, by using a perturbation expansion in the strength of the source.
(a) Show that the probability that the source creates no particles is given by
P(0)=⟨0∣T{exp[i∫d4xj(x)ϕI(x)]}∣0⟩2.
(b) Evaluate the term in P(0) of order j2, and show that P(0)=1−λ+O(j4), where λ equals the expression given above for ⟨N⟩.
(c) Represent the term computed in part (b) as a Feynman diagram. Now represent the whole pertubation series for P(0) in terms of Feynman diagrams. Show that this series exponentiates, so that it can be summed exactly: P(0)=exp(−λ).
(d) Compute the probability that the source creates one particle of momentum k. Perform this computation first to O(j) and then to all orders, using the trick of part (c) to sum the series.
(e) Show that the probability of producing n particles is given by
P(n)=(1/n!)λnexp(−λ).
This is a Poisson distribution.
(f) Prove the following facts about the Poisson distribution:
n=0∑∞P(n)=1;⟨N⟩=n=0∑∞nP(n)=λ.
The first identity says that the P(n)'s are properly normalized probabilities, while the second confirms our proposal for ⟨N⟩. Compute the mean square fluctuation ⟨(N−⟨N⟩)2⟩.