A hydrogen atom in the n=4 state (energy E4=−0.85 eV) relaxes to the ground state (E1=−13.6 eV) by first emitting a photon that brings it to the n=2 state (E2=−3.40 eV). The wavelength of this first photon is 486 nm. What is the wavelength of the second photon emitted when the atom transitions from n=2 to n=1?
a) 97 nm
b) 243 nm
c) 122 nm
d) 486 nm