Physics

Physics

Problem

A hydrogen atom in the n=4n=4 state (energy E4=−0.85 eVE_4=-0.85\text{ eV}) relaxes to the ground state (E1=−13.6 eVE_1=-13.6\text{ eV}) by first emitting a photon that brings it to the n=2n=2 state (E2=−3.40 eVE_2=-3.40\text{ eV}). The wavelength of this first photon is 486 nm. What is the wavelength of the second photon emitted when the atom transitions from n=2n=2 to n=1n=1? a) 97 nm97\text{ nm} b) 243 nm243\text{ nm} c) 122 nm122\text{ nm} d) 486 nm486\text{ nm}

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