Prove the following version of L'H\^opital's rule. Suppose f:(a,b)→R and g:(a,b)→R are differentiable functions and c∈(a,b). Suppose that f(c)=0, g(c)=0, g′(x)=0 when x=c, and that the limit of f′(x)/g′(x) as x goes to c exists. Show that
x→climg(x)f(x)=x→climg′(x)f′(x).
Compare to Exercise 4.1.15. Note: Before you do anything else, prove that g(x)=0 when x=c.