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Mathematics
Problem
Explain why the expression
3
x
+
5
(
x
−
1
)
(
x
+
2
)
(
x
+
3
)
\dfrac{3x+5}{(x-1)(x+2)(x+3)}
(
x
−
1
)
(
x
+
2
)
(
x
+
3
)
3
x
+
5
can be rewritten in the form
A
x
−
1
+
B
x
+
2
+
C
x
+
3
\dfrac{A}{x-1}+\dfrac{B}{x+2}+\dfrac{C}{x+3}
x
−
1
A
+
x
+
2
B
+
x
+
3
C
, where
A
A
A
,
B
B
B
and
C
C
C
are constants.
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