Mathematics

Problem

\frac{\sin^4 x}{2} + \frac{\cos^4 x}{3} = \frac{1}{5}

, then a.

\tan^2 x = \frac{2}{3}

\frac{\sin^8 x}{8} + \frac{\cos^8 x}{27} = \frac{1}{125}

\tan^2 x = \frac{1}{3}

\frac{\sin^8 x}{8} + \frac{\cos^8 x}{27} = \frac{2}{125}