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Mathematics
Problem
If
1
sin
20
∘
+
1
3
cos
20
∘
=
2
k
cos
40
∘
\frac{1}{\sin 20^\circ} + \frac{1}{\sqrt{3} \cos 20^\circ} = 2k \cos 40^\circ
s
i
n
2
0
∘
1
+
3
c
o
s
2
0
∘
1
=
2
k
cos
4
0
∘
, then
18
k
4
+
162
k
2
+
369
18k^4 + 162k^2 + 369
18
k
4
+
162
k
2
+
369
is equal to
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